The Al2 Cd S4 (E3) Structure
Last modified 5 April 2001
You can now
When c = 2a and x = y = 1/4, and z = 1/8 the atoms are on the sites of the diamond (A4) structure, but of course there are defects.
B1 | = | 0 | (Cd) | (2a) | ||
B2 | = | ½ A1 + ½ A2 | = | ½ a X + ½ a Y | (Al-I) | (2b) |
B3 | = | - ¼ A1 + ¼ A2 + ½ A3 | = | ½ a Y + ¼ c Z | (Al-II) | (2c) |
B4 | = | + (x-z) A1 + (y-z) A2 + 2 z A3 | = | + x a X + y a Y + z c Z | (S) | (8g) |
B5 | = | - (x+z) A1 - (y+z) A2 + 2 z A3 | = | - x a X - y a Y + z c Z | (S) | (8g) |
B6 | = | + (y+z) A1 - (x-z) A2 - 2 z A3 | = | + y a X - x a Y - z c Z | (S) | (8g) |
B7 | = | + (z-y) A1 + (x+z) A2 - 2 z A3 | = | - y a X + x a Y - z c Z | (S) | (8g) |
Go back to the Carbon and Related Structure page.
Go back to the Sulfur and its Compounds page.
Go back to Crystal Lattice Structure
page.
Structures indexed by: